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0.2x^2+6x-80=0
a = 0.2; b = 6; c = -80;
Δ = b2-4ac
Δ = 62-4·0.2·(-80)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-10}{2*0.2}=\frac{-16}{0.4} =-40 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+10}{2*0.2}=\frac{4}{0.4} =10 $
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